# Line slope calculator 5x-3y=7

**Straight line given by points A[2; 1] and B[5; 6]**

## Calculation:

**Slope-intercept form of line:**y = 1.6667x-2.3333

**Canonical form of the line equation:**5x-3y-7 = 0

**Parametric form of the line equation:**

x = 3t+2

y = 5t+1 ; t ∈ R

**Slope:**m = 1.6667

**Slope angle of line: φ =**59°2'10″ = 1.0304 rad

**X intercept:**x

_{0}= 1.4

**Y intercept:**y

_{0}= q = -2.3333

**Distance line from the origin:**d

_{0}= 1.2005

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(3; 5)

**Normal vector: n =**(5; -3)

**Midpoint of the segment AB: M =**[3.5; 3.5]

**Perpendicular Bisector equation:**3x+5y-28 = 0

**Vector OA = (2; 1) ; |OA| = 2.2361**

**Vector OB = (5; 6) ; |OB| = 7.8102**

**Scalar product OA .OB = 16**

**Angle ∠ AOB = 23°37'46″ = 0.4124 rad**